In the given figure ABCD is square and OE = 7 cm.

The perimeter of the figure is :

42 cm 44 cm 64 cm 86 cm

64 cm

OE = 7 cm = radius of semicircle Here, OE = OA = OD = 7 = radius and  AD = OA + OD = 7 + 7 = 14 cm = AB = BC = CD = side of the square Perimeter of Semi-Circle =$πr=\frac{22}{7}×7=22$cm. So, Perimeter of the above figure = Perimeter of Semi-Circle + AB + BC + CA = 22 + 14 + 14 + 14 = 64 cm.