Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:
Which of the following equation has \(y=x\) as one of its particular solution?
Options:
\(\frac{d^2 y}{dx^2}-x^2\frac{dy}{dx}+xy=x\)
\(\frac{d^2 y}{dx^2}+x\frac{dy}{dx}+xy=x\)
\(\frac{d^2 y}{dx^2}-x^2\frac{dy}{dx}+xy=0\)
\(\frac{d^2 y}{dx^2}+x\frac{dy}{dx}+xy=0\)
Correct Answer:
\(\frac{d^2 y}{dx^2}-x^2\frac{dy}{dx}+xy=0\)
Explanation:
Substitute and verify