In a transformer, the input current and voltage are 3 A and 50 V respectively. The ratio of the number of turns in the primary coil to secondary coil is 5 : 3. The output current and voltage, respectively, are

5 A and 30 V

The correct answer is Option (4) → 5 A and 30 V

Given:

$ I_p = 3 \, A , \; V_p = 50 \, V $

$ \frac{N_p}{N_s} = \frac{5}{3} $

Transformer relations:

$ \frac{V_p}{V_s} = \frac{N_p}{N_s} $

$ \frac{I_s}{I_p} = \frac{N_p}{N_s} $

From voltage relation:

$ \frac{50}{V_s} = \frac{5}{3} $

$ V_s = \frac{50 \times 3}{5} = 30 \, V $

From current relation:

$ \frac{I_s}{3} = \frac{5}{3} $

$ I_s = 5 \, A $

Final result:

Output current $= 5 \, A$

Output voltage $= 30 \, V$