Practicing Success
A cyclic process for 1 mole of an ideal gs is shown in the given figure in the V-T, diagram. The work done in AB, BC and CA, respectively, is : |
\(0, RT_2 ln (\frac{V_1}{V_2}, R(T_1-T_2)\) \(R(T_1-T_2), 0, RT_1 ln (\frac{V_1}{V_2}\) \(0, RT_2 ln (\frac{V_2}{V_1}, R(T_1-T_2)\) \(0, RT_2 ln (\frac{V_2}{V_1}, R(T_2-T_1)\) |
\(0, RT_2 ln (\frac{V_2}{V_1}, R(T_2-T_1)\) |
Process AB is isochoric; \(\Rightarrow W_{AB} = P \Delta V = 0\) Process BC is isothermal; \(\Rightarrow W_{BC} = RT_2 ln (\frac{V_2}{V_1})\) Process CA is isobaric; \(\Rightarrow W_{CA} = P \Delta V = R \Delta T = R(T_2 - T_1)\) |