A cyclic process for 1 mole of an ideal gs is shown in the given figure in the V-T, diagram. The work done in AB, BC and CA, respectively, is :
Answer & explanation
Correct answer: option 4
Process AB is isochoric;
\(\Rightarrow W_{AB} = P \Delta V = 0\)
Process BC is isothermal;
\(\Rightarrow W_{BC} = RT_2 ln (\frac{V_2}{V_1})\)
Process CA is isobaric;
\(\Rightarrow W_{CA} = P \Delta V = R \Delta T = R(T_2 - T_1)\)