Practicing Success
Which of the following species is diamagnetic? |
An isolated, gas-phase V3+ ion A high spin octahedral Fe2+ complex An isolated, gas phase Cu2+ ion A low spin octahedral Co3+ complex |
A low spin octahedral Co3+ complex |
The correct answer is option 4. A low spin octahedral \(Co^{3+}\) complex. To determine which species is diamagnetic, let us analyze each option based on their electron configurations and the magnetic properties associated with them: 1. An isolated, gas-phase \(V^{3+}\) ion: Vanadium in the \(+3\) oxidation state (\(V^{3+}\)) has the electron configuration \([Ar] 3d^2\). Configuration: \(3d^2\). This configuration has 2 unpaired electrons, making it paramagnetic, not diamagnetic. Iron in the \(+2\) oxidation state (\(Fe^{2+}\)) typically has the electron configuration \([Ar] 3d^6\). High spin octahedral complexes typically have a \(t_{2g}^4 e_g^2\) configuration in an octahedral crystal field. Configuration: \(3d^6\). This configuration has 4 unpaired electrons, making it paramagnetic, not diamagnetic. Copper in the +2 oxidation state (\(Cu^{2+}\)) has the electron configuration \([Ar] 3d^9\). Configuration: \(3d^9\). This configuration has 1 unpaired electron, making it paramagnetic, not diamagnetic. Cobalt in the \(+3\) oxidation state (\(Co^{3+}\)) typically has the electron configuration \([Ar] 3d^6\). Low spin octahedral complexes typically have a \(t_{2g}^6\) configuration in an octahedral crystal field. Configuration: \(3d^6\). This configuration has 0 unpaired electrons, making it diamagnetic. The species that is diamagnetic among the given options is: \(\text{A low spin octahedral }Co^{3+} \text{ complex}\) |