The resistance of a metallic wire becomes 8 times when
Answer & explanation
Correct answer: option 3
$R= \frac{\rho l}{A} \propto \frac{l}{r^2}$
$\text{R become 8 times when length is doubled and radius is halved.}$
The resistance of a metallic wire becomes 8 times when
Correct answer: option 3
$R= \frac{\rho l}{A} \propto \frac{l}{r^2}$
$\text{R become 8 times when length is doubled and radius is halved.}$