Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

What is the value of $\frac{8×5÷25}{7÷14×2}-\frac{14÷7-5}{7÷14-25}$?

Options:

$\frac{362}{245}$

$\frac{115}{245}$

$\frac{306}{245}$

$\frac{106}{245}$

Correct Answer:

$\frac{362}{245}$

Explanation:

$\frac{8×5÷25}{7÷14×2}-\frac{14÷7-5}{7÷14-25}$

= $\frac{8÷5}{1}-\frac{-3}{1÷2-25}$

= $\frac{8÷5}{1}-\frac{-6}{-49}$

= $\frac{8}{5}-\frac{6}{49}$

= $\frac{362}{245}$