What is the value of $\frac{8×5÷25}{7÷14×2}-\frac{14÷7-5}{7÷14-25}$?
Answer & explanation
Correct answer: option 1
$\frac{8×5÷25}{7÷14×2}-\frac{14÷7-5}{7÷14-25}$
= $\frac{8÷5}{1}-\frac{-3}{1÷2-25}$
= $\frac{8÷5}{1}-\frac{-6}{-49}$
= $\frac{8}{5}-\frac{6}{49}$
= $\frac{362}{245}$