The area (in sq. units) of the triangle whose vertices are (0, 0), (a, 0), (0, b), is equal to
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\frac{1}{2}|ab|$
Vertices: $(0,0),\ (a,0),\ (0,b)$
Area of triangle $=\frac{1}{2}\left|x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right|$
$=\frac{1}{2}\left|0(0-b)+a(b-0)+0(0-0)\right|$
$=\frac{1}{2}|ab|$