If the random variable x has the following distribution:
Match List-I with List-II
Choose the correct answer from the options given below. |
(A)-(I), (B)-(III), (C)-(II), (D)-(IV) (A)-(II), (B)-(III), (C)-(I), (D)-(IV) (A)-(I), (B)-(IV), (C)-(III), (D)-(II) (A)-(II), (B)-(III), (C)-(IV), (D)-(I) |
(A)-(II), (B)-(III), (C)-(IV), (D)-(I) |
The correct answer is Option (4) → (A)-(II), (B)-(III), (C)-(IV), (D)-(I) **
Given distribution:
X : 0, 1, 2 Total probability = 1: $k + k + 2k = 4k = 1 \Rightarrow k = \frac{1}{4}$ Now compute: $P(x \ge 2) = P(2) = 2k = \frac{1}{2}$ $P(X \le 2) = P(0) + P(1) + P(2) = 1$ $P(0 < x \le 2) = P(1) + P(2) = k + 2k = 3k = \frac{3}{4}$ Final answer: (A)–(II), (B)–(III), (C)–(IV), (D)–(I) |