If sin B = 9/41, then what is the value of cot B, where 0° < B < 90° ?

sinB = \(\frac{9}{41}\)

{ sinB = \(\frac{P}{H}\) }

P² + B² = H²

9² + B² = 41²

B = 40

Now,

cotB

= \(\frac{B}{P}\) 

= \(\frac{40}{9}\)