Practicing Success
Practicing Success
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If sin B = $\frac{9}{41}$, then what is the value of cot B, where 0° < B < 90° ? |
$\frac{41}{9}$ $\frac{40}{9}$ $\frac{9}{41}$ $\frac{9}{40}$ |
$\frac{40}{9}$ |
sinB = \(\frac{9}{41}\) { sinB = \(\frac{P}{H}\) } P² + B² = H² 9² + B² = 41² B = 40 Now, cotB = \(\frac{B}{P}\) = \(\frac{40}{9}\) |
