A proton and an electron moving with same kinetic energy enter uniform magnetic field at right- angle to its direction. The ratio of radii of their trajectories will be: |
43 :1 $1: \sqrt{2}$ $1: 1$ $1: 2$ |
43 :1 |
The correct answer is Option 1: 43 : 1 $r=\frac{\sqrt{2m \, K.E}}{qB}$, q is same for both electron and proton. $⇒r ∝ \sqrt{m}⇒\frac{r_p}{m_e}=\sqrt{\frac{m_p}{m_e}}=\sqrt{\frac{1.67\times 10^{-27}}{9.1\times 10^{-31}}}$ $⇒\frac{r_p}{r_e}=\sqrt{\frac{m_p}{m_e}}$ Since, mₚ ≈ 1836 mₑ rₚ / rₑ = √1836 / 1 ≈ 43 :1 ** |