Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If a + b + c = 0, then the value of $\frac{a^{2}}{bc}+\frac{b^{2}}{ca}+\frac{c^{2}}{ab}$ is :

Options:

1

3

-1

0

Correct Answer:

3

Explanation:

If a + b + c = 0,

Then the value of $\frac{a^{2}}{bc}+\frac{b^{2}}{ca}+\frac{c^{2}}{ab}$

Put the value of a = 2 , b = -1 and c = -1

$\frac{2^{2}}{-1 \times -1}+\frac{-1^{2}}{-1 \times 2}+\frac{-1^{2}}{2 \times -1}$

= 4 - \(\frac{1}{2}\) - \(\frac{1}{2}\) = 3