A photo cathode is illuminated by a very small bright source placed 1 m away. When the same source of light is placed 0.5 m away, the number of electrons emitted by the photo cathode would become |
four times twice one fourth half |
four times |
The correct answer is Option (1) → four times Intensity ∝ 1/r² When distance changes from 1 m to 0.5 m: $\frac{ New intensity }{ Old intensity } = \frac{(1 / 0.5²)}{(1 / 1²)} = 4$ ∴ Number of electrons emitted ∝ Intensity ⇒ Increases 4 times Answer: 4 times |