The probability distribution of a random variable X is given below:
|
X |
-5 |
-4 |
-3 |
-2 |
-1 |
0 |
1 |
2 |
3 |
4 |
5 |
|
P(X) |
p |
2p |
3p |
4p |
5p |
7p |
8p |
9p |
10p |
11p |
12p |
Then the value of p is:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → $\frac{1}{72}$
$∑P(X)=1$
$⇒(1+2+....+12)P=1$
$⇒P=\frac{1}{72}$