If the probability distribution of a random variable X is as given below :
|
X |
-1 |
0 |
1 |
2 |
3 |
|
P(X) |
K |
$\frac{1}{5}$ |
2K |
$\frac{3}{10}$ |
K |
Then the value of K is :
Answer & explanation
Correct answer: option 4
|
X |
-1 |
0 |
1 |
2 |
3 |
|
P(X) |
K |
$\frac{1}{5}$ |
2K |
$\frac{3}{10}$ |
K |
we know that $\sum P\left(x_i\right)=1$
$\Rightarrow K+\frac{1}{5}+2 K+\frac{3}{10}+K=1$
So $4K + \frac{2+3}{10} = 1$
$4K + \frac{5}{10} = 1$
$K = \frac{6}{10}$
$K = \frac{1}{2×4}$
$K = \frac{1}{8}$