Practicing Success
Practicing Success
CUET Preparation Today
$\lim\limits_{x \rightarrow \infty}\left(\frac{x+6}{x+1}\right)^{x+4}$ |
0 1 $e^4$ $e^5$ |
$e^5$ |
$1^{\infty}$ form, given limit equal to $e^{\lim\limits_{X \rightarrow 0}(x+4) \frac{5}{x+1}}=e^5$ Hence (4) is the correct answer. |
