If $f(x)=x^{x^{x ... \infty}}$ then $f'(x)=$ |
$\frac{(f(x))^2}{x(1+f(x) \log x)}$ $\frac{(f(x))^2}{x(1-f(x) \log x)}$ $\frac{f(x)}{x(1+f(x) \log x)}$ $\frac{f(x)}{x(1-f(x) \log x)}$ |
$\frac{(f(x))^2}{x(1-f(x) \log x)}$ |
The correct answer is Option (2) → $\frac{(f(x))^2}{x(1-f(x) \log x)}$ |