CUET Preparation Today
if sin P =$\frac{15}{22}$, then what is the value of tan P ? |
$\frac{16}{\sqrt{259}}$ $\frac{22}{\sqrt{259}}$ $\frac{14}{\sqrt{259}}$ $\frac{15}{\sqrt{259}}$ |
$\frac{15}{\sqrt{259}}$ |
We are given :- sinP = \(\frac{15}{22}\) { we know, sinP = \(\frac{P}{H}\) } By using pythagoras theorem, P² + B² = H² 15² + B² = 22² B² = 484 - 225 B = \(\sqrt {259 }\) Now, tanP = \(\frac{P}{B}\) = \(\frac{15}{ √259}\) |
