The value of $∫(5x-2)^3dx$ is :
Answer & explanation
Correct answer: option 4
$∫(5x-2)^3dx$
$=\frac{1×(5x-2)^{3+1}}{5×(3+1)}+C$
$=\frac{(5x-2)^4}{20}+C$ Using $∫(ax-b)^ndx=\frac{(ax-b)^{n+1}}{a×(n+1)}+C$
The value of $∫(5x-2)^3dx$ is :
Correct answer: option 4
$∫(5x-2)^3dx$
$=\frac{1×(5x-2)^{3+1}}{5×(3+1)}+C$
$=\frac{(5x-2)^4}{20}+C$ Using $∫(ax-b)^ndx=\frac{(ax-b)^{n+1}}{a×(n+1)}+C$