If the momentum of electron is changed by P then the de Broglie wavelength associated with it changes by 1 %. The initial momentum of electron will be :
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 100 P
The de Broglie wavelength is inversely proportional to the momentum.
\( \displaystyle \lambda = \frac{h}{p} \)
For a small change, the fractional change in \( \lambda \) equals the fractional change in \( p \) (only the sign is opposite).
\( \displaystyle \left|\frac{\Delta\lambda}{\lambda}\right| = \frac{\Delta p}{p} \)
Putting \( \Delta p = P \) and a change of 1% in the wavelength,
\( \displaystyle \frac{P}{p} = \frac{1}{100} \;\Rightarrow\; p = 100\,P \)