A common emitter transistor amplifier has a current gain of 50. If the load resistance is 4 kΩ and input resistance is 500Ω, the voltage gain of the amplifier is:
Answer & explanation
Correct answer: option 4
Here, $β= 50, R_L = 4kΩ= 4×10^3Ω$ $R_i =500Ω$
Voltage gain, $A_v=β\frac{R_L}{R_i}=50×\frac{4×10^3}{500}=400$