There is a parallel plate capacitor of capacitance 3 μF. The voltage between the plates of parallel plate capacitor is changing at the rate of 8 V/s. The displacement current produced is:

24 μΑ

The correct answer is Option (2) → 24 μΑ

The displacement current ($I_d$) in a capacitor is -

$I_{displacement}=C\frac{dV}{dt}$

$=3×10^{-6}×8$

$=24μA$