There is a parallel plate capacitor of capacitance 3 μF. The voltage between the plates of parallel plate capacitor is changing at the rate of 8 V/s. The displacement current produced is:
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 24 μΑ
The displacement current ($I_d$) in a capacitor is -
$I_{displacement}=C\frac{dV}{dt}$
$=3×10^{-6}×8$
$=24μA$