In the following figure, if angles ∠ABC = 75°, ∠FED = 135° then the angle ∠APC is equal to?

150°

∠AFC = 180° - 75° = 105°

(opposite angle in cyclic quadrilateral)

∠AFC = ∠ADC = 105° (angle on same arc AC)

∠FCD = 180° - 135° = 45° (opposite angle in cyclic quadrilateral)

∠APC = ∠PDC + ∠PCD (exterior angle)

         = 105° + 45° = 150°