In the following figure, if angles ∠ABC = 75°, ∠FED = 135° then the angle ∠APC is equal to?
Answer & explanation
Correct answer: option 1
∠AFC = 180° - 75° = 105°
(opposite angle in cyclic quadrilateral)
∠AFC = ∠ADC = 105° (angle on same arc AC)
∠FCD = 180° - 135° = 45° (opposite angle in cyclic quadrilateral)
∠APC = ∠PDC + ∠PCD (exterior angle)
= 105° + 45° = 150°