Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Induction

Question:

Case : Read the passage and answer the question(s).

Let us consider a straight conductor moving in a uniform and time-independent magnetic field. Figure shows a rectangular conductor PQRS in which the conductor PQ is free to move. The rod PQ is moved towards the left with a constant velocity v as shown in the figure. PQRS forms a closed circuit enclosing an area that changes as PQ moves. The length RQ = x and RS = l and the magnetic flux is ΦB enclosed by the loop PQRS.

The work done in moving the charge from Q to P is given by which of the following?

Options:

Kinetic energy stored in charge

EMF per unit charge

Potential energy stored in charge

qlvB

Correct Answer:

qlvB

Explanation:

Expression for work done = qlBv