The speeds of two bodies are in the ratio 2 : 3. If the difference in the time taken to cover 50 m is 10 sec, then find the difference in their speeds.
Answer & explanation
Correct answer: option 2
Let the speed of two bodies be 2S and 3S respectively.
Time taken by first body to cover 50 m = \(\frac{50}{2x}\)
Time taken by second body to cover 50 m = \(\frac{50}{3x}\)
According to the question,
\(\frac{50}{2x}\) - \(\frac{50}{2x}\) = 10
50 = 10 × 6 x
x = \(\frac{50}{60}\)
= \(\frac{5}{6}\)
Difference in speed = 3x - 2x = x
= \(\frac{5}{6}\) m/sec