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CUET
-- Applied Mathematics - Section B2
Numbers, Quantification and Numerical Applications
$37-(3x+5) ≥9x-8(x-3)$
(-∞, 3]
(-∞, 2]
(-∞, 4]
(-∞, 5]
The correct answer is option (2) : (-∞, 2]
$37-3x-5 ≥9x-8x+24$
$32-3x ≥x+24$
$-4x ≥-8$
$x≤2$
∴ Solution is (-∞, 2]
