$37-(3x+5) ≥9x-8(x-3)$
Answer & explanation
Correct answer: option 2
The correct answer is option (2) : (-∞, 2]
$37-(3x+5) ≥9x-8(x-3)$
$37-3x-5 ≥9x-8x+24$
$32-3x ≥x+24$
$-4x ≥-8$
$x≤2$
∴ Solution is (-∞, 2]
$37-(3x+5) ≥9x-8(x-3)$
Correct answer: option 2
The correct answer is option (2) : (-∞, 2]
$37-(3x+5) ≥9x-8(x-3)$
$37-3x-5 ≥9x-8x+24$
$32-3x ≥x+24$
$-4x ≥-8$
$x≤2$
∴ Solution is (-∞, 2]