Practicing Success
The feasible region of an LPP Max $Z=3x+2y$ subject to $x ≥0, y≥0, x-2y≤3$ is: |
Bounded in first quadrant but has no solution Unbounded in first quadrant but has a solution Unbounded in first quadrant and has no solution Bounded and has a solution $x = 0, y = 0, Z=0$ |
Unbounded in first quadrant and has no solution |
$Z=3x+2y$ $x ≥0, y≥0$ → solution in first quadrant plotting $x-2y=3$ first
now checking for (0, 0) $x - 2y ≤3$ $⇒0≤3$ So solution has two side of $x-2y=3$ containing (0, 0) |