If x - \(\frac{1}{x}\) = 3\(\sqrt{2}\) then find the value of  ( x + \(\frac{1}{x}\) )

\(\sqrt{22}\)  \(\sqrt{23}\)  4\(\sqrt{2}\)  3\(\sqrt{22}\)

\(\sqrt{22}\)

⇒ If x - \(\frac{1}{x}\) = a then x + \(\frac{1}{x}\) = \(\sqrt {a^2 + 4}\) Here, x - \(\frac{1}{x}\) = 3\(\sqrt{2}\), then  ⇒ x + \(\frac{1}{x}\) = \(\sqrt {(3\sqrt{2})^2 + 4}\) = \(\sqrt{22}\)