A circle is inscribed in the triangle ABC whose sides are given as AB = 10, BC = 8, CA= 12 units as shown in the figure. The value of AD × BF is:
Answer & explanation
Correct answer: option 2
We have,
AB = 10, BC = 8, CA= 12
Semi Perimeter of the triangle = \(\frac{10 + 8 + 12}{2}\) = 15
Now the value of AD = 15 - BC
= 15 - 8 = 7
And the value of BF = 15 - AC
= 15 - 12 = 3
So, the value of AD × BF = 7 × 3 = 21 units