Practicing Success
Practicing Success
CUET Preparation Today
In ΔABC, AB = AC, and ∠BAC is 50°. Then ∠ABC and ∠BCA are, respectively: |
50° and 55° 65° and 65° 70° and 75° 55° and 55° |
65° and 65° |
We have, AB = AC ∠BAC = 50o According to the question, As AB = AC so, ∠ABC = ∠BCA = ∠ABC + ∠BCA + ∠BAC = 180° = ∠ABC + ∠BCA = 180° – 50° = ∠ABC + ∠BCA = 130° = ∠ABC + ∠ABC = 130° = 2∠ABC = 130° = ∠ABC = ∠BCA = 65° |
