In ΔABC, AB = AC, and ∠BAC is 50°. Then ∠ABC and ∠BCA are, respectively:
Answer & explanation
Correct answer: option 2
We have,
AB = AC
∠BAC = 50o
According to the question,
As AB = AC so, ∠ABC = ∠BCA
= ∠ABC + ∠BCA + ∠BAC = 180°
= ∠ABC + ∠BCA = 180° – 50°
= ∠ABC + ∠BCA = 130°
= ∠ABC + ∠ABC = 130°
= 2∠ABC = 130°
= ∠ABC = ∠BCA = 65°