Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

General Knowledge

Topic

Chemistry

Question:

How can the permanent hardness of water be removed? 

Options:

Na2CO3

K

Ca(OCl)Cl

Cl2

Correct Answer:

Na2CO3

Explanation:

The correct answer is option 1. Na2CO3.

The permanent hardness of water, which is mainly due to the presence of calcium and magnesium ions, can be removed by using sodium carbonate \((Na_2CO_3)\). Sodium carbonate reacts with calcium and magnesium ions to form insoluble carbonates, which can then be removed through precipitation. The chemical equation for the reaction is:

\[ \text{Ca(HCO3)2 (aq) + Na2CO3 (aq) → CaCO3 (s) + 2NaHCO3 (aq)} \]

\[ \text{Mg(HCO3)2 (aq) + Na2CO3 (aq) → MgCO3 (s) + 2NaHCO3 (aq)} \]

The formed calcium carbonate \((CaCO_3)\) and magnesium carbonate \((MgCO_3)\) are insoluble and can be separated from the water, thus reducing the hardness.