Air is filled at 60oC in a vessel of open mouth. The vessel is heated to a temperature T so that 1/4th part of air escapes. Assuming the volume of vessel remaining constant, the value of T is :
Answer & explanation
Correct answer: option 4
\(M_1 = M ; T_1 = 60 + 273 = 333 K\)
\(M_2 = M - \frac{M}{4} = \frac{3M}{4}\) ... [as 1/4th part of air escapes]
If pressure and volume of the gas remain constant, then :
MT = constant
\(\Rightarrow \frac{T_2}{T_1} = \frac{M_1}{M_2} = \frac{M}{3M/4} = frac{4}{3}\)
\(T_2 = \frac{4}{3} T_1 = \frac{4}{3}*333\)
\(T_2 = 444 K\) = 171oC