Figure shows a metal rod PQ resting on the rails AB and positioned between the poles of a permanent magnet. The rails, the rod and the magnetic field are in three mutual perpendicular directions. A galvanometer G connects the rails through a switch K. Length of the rod = 15 cm, B = 0.50 T, resistance of the closed loop containing the rod = 180.0 $m\Omega$. Assume the field to be uniform.

Suppose K is open and the rod is moved with a speed of $12 ~cms^{-1}$ in the direction. The magnitude of the induced emf will be:

$9.0 \times 10^{-3} V$

The correct answer is Option (2) → $9.0 \times 10^{-3} V$