The degree of the differential equation of all tangent lines to the parabola $y^2=4ax$ is:
Answer & explanation
Correct answer: option 2
Equation of tangent to the parabola $y^2=4ax$ is $y=mx+\frac{a}{m}$, m is any arbitrary constant and $\frac{dy}{dx}=m$.
$⇒y=x\frac{dy}{dx}+\frac{a}{\frac{dy}{dx}}⇒x.(\frac{dy}{dx})^2-y\frac{dy}{dx}+a=0$