Practicing Success
Practicing Success
CUET Preparation Today
Which of the following is a correct relation for a transistor |
$α=\frac{β}{1-β}$ $β=\frac{α}{1-α}$ $β=\frac{α}{1+α}$ $α=\frac{β}{1+α}$ |
$β=\frac{α}{1-α}$ |
$I_E = I_B + I_C$ Differentiating, we get $ΔI_E = ΔI_B + ΔI_C$ $⇒\frac{ΔI_E}{ΔI_C}=\frac{ΔI_B}{ΔI_C}+1$ $⇒\frac{1}{α}=\frac{1}{β}+1=\frac{1+β}{β}$ $⇒α=\frac{β}{1+β}$
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