A triangle ABC is inscribed in a circle with center O. AO is produced to meet the circle at K and AO is angle bisector of A and AD ⊥ BC. If ∠B = 70° and ∠C = 54°, the the measure of ∠DAK is?
Answer & explanation
Correct answer: option 4
∠DAK = \(\frac{∠B - ∠C}{2}\) = \(\frac{70 - 54}{2}\) = 8°