Practicing Success
Let $f(x)=(x+1)^2-1,x≥-1$ Statement 1 : The set $\{x:f(x)=f^{-1}(x)\}=\{0,-1\}$ Statement 2 : f is a bijection |
Statement 1 is true, Statement 2 is true ; Statement 2 is a correct explanation for Statement 1 Statement 1 is true, Statement 2 is true ; Statement 2 is not correct explanation for Statement 1 Statement 1 is true, Statement 2 is false Statement 1 is false, Statement 2 is true |
Statement 1 is true, Statement 2 is false |
There is no information about co-domain therefore f (x) is not necessarily onto. |