Which of the following particle will experience maximum magnetic force (magnitude) when projected with same velocity perpendicular to the magnetic field ?
Choose the correct answer from the options given below.
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → \( \mathrm{Li^{++}} \)
The magnetic force on a charge moving perpendicular to the field is \( F = qvB \). With the same \( v \) and \( B \), the force depends only on the magnitude of the charge; the mass does not enter.
\( \mathrm{Electron:}\ |q| = e \)
\( \mathrm{Proton:}\ |q| = e \)
\( \mathrm{He^{+}:}\ |q| = e \)
\( \mathrm{Li^{++}:}\ |q| = 2e \)
\( \mathrm{Li^{++}} \) has the largest charge, so it experiences the maximum force, \( 2evB \).