A carbon resistance of 4.7 kΩ is to be marked with strips or bands of different colours for its identification. The sequence of colours would be:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → yellow, violet, red
In the resistor colour code the first two bands give the first two significant figures and the third band gives the power of ten by which they are multiplied.
\( 4.7\,\mathrm{k\Omega} = 4700\,\Omega = 47\times10^{2}\,\Omega \)
First digit 4 is yellow, second digit 7 is violet, and the multiplier \( 10^{2} \) is red (red stands for 2).
Note: This question is from the pre-rationalised NCERT book (2022-23). The topic was removed from the latest NCERT book (2026-27), and it also appears to be out of the CUET 2026 syllabus.
NCERT (Pre-rationalised edition, 2022-23):
Resistivity of Various Materials – …
