In a 1000 m race A gives a start of 100m to B and 150m to C. How much start can B give to C in a race of 1000 m. |
54\(\frac{2}{9}\) m 55\(\frac{5}{9}\) m 57\(\frac{5}{9}\) m 58\(\frac{2}{9}\)m |
55\(\frac{5}{9}\) m |
A : B : C 1000m 900m 850m in a race of 900m, B gives a 50 meters start to C for 1000m ⇒ 900m → 50m 1000m → \(\frac{50}{900}\) × 1000 = 55\(\frac{5}{9}\) meters |