The area common to the curves $y=x^3$ and $y=\sqrt{x}$ is
Answer & explanation
Correct answer: option 4
$A= \int\limits_0^1\left(\sqrt{x}-x^3\right) dx$
$=\frac{2}{3}\left|x^{3 / 2}\right|_0^1-\left|\frac{x^4}{4}\right|_0^1$
$=\frac{2}{3}-\frac{1}{4}=\frac{8-3}{12}=\frac{5}{12}$