Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

A satellite of mass m revolves around the earth of radius R at a height x from its surface. If g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is :

Options:

\(\sqrt{\frac{gR}{R-x}}\)

\(\sqrt{\frac{gR^2}{R-x}}\)

\(\sqrt{gx}\)

\(\sqrt{\frac{gR^2}{R+x}}\)

Correct Answer:

\(\sqrt{\frac{gR^2}{R+x}}\)

Explanation:

\(mg (1 + \frac{x}{R})^{-2} = \frac{mv^2}{R+x}\)

\(\Rightarrow v = \sqrt{g(R+x)\frac{R^2}{(R+x)^2}}\)

\(\Rightarrow v = \sqrt{\frac{gR^2}{R+x}}\)