The following table shows the weight of 20 students:
| Weight (in kg) | 48 | 51 | 60 | 53 | 56 |
| No. of Students | 6 | 3 | 2 | 4 | 5 |
The mode and median of the above data are, respectively:
Answer & explanation
Correct answer: option 4
Mode is term with maximum frequency.
By observing table ,
Mode = 48
Total number of students = 6 + 3 + 2 + 4 + 5 = 20 ( even number )
Median ( if even number ) = \(\frac{(n/2)th + (n/2 + 1 )th }{2}\)
= \(\frac{10th + 11th }{2}\)
= \(\frac{53 + 53 }{2}\)
= 53