The following table shows the weight of 20 students: Weight (in kg) 48 51 60 53 56 No. of Students 6 3 2 4 5 The mode and median of the above data are, respectively:

53 and 56 60 and 53 51 and 48 48 and 53

48 and 53

Mode is term with maximum frequency. By observing table , Mode = 48 Total number of students = 6 + 3 + 2 + 4 + 5 = 20 ( even number ) Median ( if even number ) = \(\frac{(n/2)th + (n/2 + 1 )th  }{2}\) = \(\frac{10th + 11th }{2}\) = \(\frac{53 + 53 }{2}\)  = 53