The following table shows the weight of 20 students:

The mode and median of the above data are, respectively:

48 and 53

Mode is term with maximum frequency.

By observing table ,

Mode = 48

Total number of students = 6 + 3 + 2 + 4 + 5 = 20 ( even number )

Median ( if even number ) = \(\frac{(n/2)th + (n/2 + 1 )th  }{2}\)

= \(\frac{10th + 11th }{2}\)

= \(\frac{53 + 53 }{2}\) 

= 53