The sides of an isosceles triangles are 10 cm, 10 cm and 12 cm. What is the area of the triangle?

60 cm2 48 cm2 40 cm2 44 cm2

48 cm2

We know that, Area of right angled triangle = \(\frac{1}{2}\) × Base × Height The sides of isosceles triangle = 10, 10 and 12 So the base is 12. Half of the base = 6 = base Then height = 102 = 62 + h2 h = 8 So area = 2 × \(\frac{1}{2}\) × 6 × 8 = 48cm2