The sides of an isosceles triangles are 10 cm, 10 cm and 12 cm. What is the area of the triangle?

48 cm²

We know that,

Area of right angled triangle = \(\frac{1}{2}\) × Base × Height

The sides of isosceles triangle = 10, 10 and 12

So the base is 12.

Half of the base = 6 = base

Then height = 10² = 6² + h²

h = 8

So area = 2 × \(\frac{1}{2}\) × 6 × 8 = 48cm²