Solution of the differential equation $\frac{dy}{dx}+\frac{3x}{2y}=0$ with y(1)= 1 is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $2y^2+3x^2=5$
$\frac{dy}{dx}+\frac{3x}{2y}⇒∫2ydy=∫-3xdx$
so $y^2=-\frac{3}{2}x^2+C$
at $x = 1,y=1$
$⇒1=-\frac{3}{2}+C⇒C=\frac{5}{2}$
so eq. ⇒ $y^2=-\frac{3}{2}x^2+\frac{5}{2}$
$⇒2y^2+3x^2=5$