A can do a work in 12 days. B's efficiency to do the work is 50% more than that of A. In how many days will B be able to do the work?
Answer & explanation
Correct answer: option 1
A alone can do the work in = 12 days
B's efficiency = 50% more than A's efficiency
Total work = Efficiency × Number of days to finish the work
Efficiency Ratio of A and B
A ∶ B = 100 ∶ 150 = 2 ∶ 3
Let A's efficiency = 2a then B's efficiency = 3a
Now, total work done by A = 2a × 12 = 24a
Same work done by B in = 24a ÷ 3a = 8 days