A can do a work in 12 days. B's efficiency to do the work is 50% more than that of A. In how many days will B be able to do the work? |
8 10 5 11 |
8 |
A alone can do the work in = 12 days B's efficiency = 50% more than A's efficiency Total work = Efficiency × Number of days to finish the work Efficiency Ratio of A and B A ∶ B = 100 ∶ 150 = 2 ∶ 3 Let A's efficiency = 2a then B's efficiency = 3a Now, total work done by A = 2a × 12 = 24a Same work done by B in = 24a ÷ 3a = 8 days |