If the mean of Binomial distribution is 5 and Variance is 3 then the value of p(probability of success ) is :

$\frac{1}{5}$ $\frac{2}{5}$ $\frac{3}{5}$ $\frac{4}{5}$

$\frac{2}{5}$

The correct answer is Option (2) → $\frac{2}{5}$ $μ=np=5$ $σ=npq=3$ so $\frac{np}{npq}=\frac{5}{3}$ so $q=\frac{3}{5}$ $p=1-q=\frac{2}{5}$