If \(\frac{a}{9}\) = \(\frac{b}{7}\

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Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If \(\frac{a}{9}\) = \(\frac{b}{7}\) = \(\frac{c}{6}\)

then find (\(\frac{a + b }{a + b + c }\)).

Options:

\(\frac{17}{24}\)

\(\frac{23}{24}\)

\(\frac{17}{19}\)

Correct Answer:

\(\frac{17}{24}\)

Explanation:

Given, \(\frac{a}{9}\) = \(\frac{b}{8}\) = \(\frac{c}{7}\)

Here we can directly conclude that

a = 9, b = 8, c = 7, hence

⇒ (\(\frac{a + b }{a + b + c }\)) = (\(\frac{9 + 8 }{9 + 8 + 7 }\))= \(\frac{17}{24}\)