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The work function of a metal in 4 eV. For the emission of photoelectrons of zero velocity from the metal surface, the wavelength of the incident radiation should be |
1700 Å 2700 Å 3100 Å 5900 Å |
3100 Å |
$\lambda_{max} = \frac{hc}{\phi} = \frac{12400 Å}{4} = 3100Å$ |
