What is the value of $\frac{1+sinA}{cos^2A}$ ?

$\frac{1}{1-sinA}$ $\frac{1}{1+sinA}$ $\frac{1}{1+cosA}$ $\frac{1}{1-cosA}$

$\frac{1}{1-sinA}$

\(\frac{1 + sinA}{cos²A}\) { using , sin²A + cos²A = 1 } = \(\frac{1 + sinA}{ 1 - sin²A}\) = \(\frac{1 + sinA}{ (1 - sinA) . ( 1 + sinA)}\) = \(\frac{1}{ (1 - sinA) }\)