What is the value of $\frac{1+sinA}{cos^2A}$ ?
Answer & explanation
Correct answer: option 1
\(\frac{1 + sinA}{cos²A}\)
{ using , sin²A + cos²A = 1 }
= \(\frac{1 + sinA}{ 1 - sin²A}\)
= \(\frac{1 + sinA}{ (1 - sinA) . ( 1 + sinA)}\)
= \(\frac{1}{ (1 - sinA) }\)